$2\left(10\right)^4-\left(10\right)^2-1$
$\sqrt{x}+\sqrt{y}y'=0$
$10ab;\:a=1;\:b=2$
$1^{-4.5}$
$\sqrt{294x^2}$
$\int\frac{1}{\left(9t^2+16\right)^2}dx$
$\sqrt{43.5}\left(21.5\right)\left(14.25\right)\left(7.5\right)$
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