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Exercise

dydx=(x+3y)−(x−y)\frac{dy}{dx}=\frac{\left(x+3y\right)}{-\left(x-y\right)}

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Final answer to the exercise

ln⁡∣5y(x+2y)2−5y2∣+36161ln⁡∣xy+2+5∣−36161ln⁡∣xy+2−5∣=ln⁡∣y∣+C0\ln\left|\frac{\sqrt{5}y}{\sqrt{\left(x+2y\right)^2-5y^2}}\right|+\frac{36}{161}\ln\left|\frac{x}{y}+2+\sqrt{5}\right|-\frac{36}{161}\ln\left|\frac{x}{y}+2-\sqrt{5}\right|=\ln\left|y\right|+C_0

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dydx =(x+3y)−(x−y) 
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