$\frac{4}{9}z-\frac{3}{9}z+2-\frac{5}{9}z-9$
$45\left(-39\right)+10+11$
$\left(2x^3+5\right)\left(2x^3-4\right)$
$-8-15-19\:4-29\:100-1$
$12.59+1.98+350.9$
$\frac{1-\left(\sin\left(x\right)\right)^4}{1+\:\left(\sin\left(x\right)\right)^2}=\left(\cos\left(x\right)\right)^2$
$\left(2a+8b^3\right)\left(2a-8b^3\right)$
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