$\lim_{x\to\frac{\pi}{4}}\left(\frac{\sec\left(2x\right)}{1-\tan\left(x\right)}\right)$
$2a^2+a=1$
$x^2+3x+64$
$0 - 4 - 8 ( 2 + 9 - 3 ) - 2$
$\left(ab^2+2x\right)^2$
$\frac{3}{4}x+5=11$
$-4x^3+150x+36$
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