$\left(2x^3-6x\:+8\right):\left(x+4\right)$
$\left(z^9\right)^2$
$-37+-7+-11+18$
$\lim_{x\to0}\left(\frac{\left(x^2+2x\right)}{\sin\left(2x\right)}\right)$
$10^3$
$-x^4-2x^2+x+3;\:x=2$
$\left(1-3ax\right)\left(3ax\:+\:1\right)\:=\:1\:-\:9a^2x^2$
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