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f(x)=(3x+1)/2−6−5−4−3−2−10123456−3-2.5−2-1.5−1-0.500.511.522.53xy

Exercise

lim⁡x→∞(3x+12)\lim_{x\to\infty}\left(\frac{3x+1}{2}\right)

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Final answer to the exercise

∞\infty

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limx→∞(3x+12 )
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