$\int_0^4-\sqrt{16-\left(x-4\right)^2}dx$

$8cosx+8cos\left(2b\right)$

$\sqrt[3]{2}^{\sqrt{3}}^.^{\sqrt{3}}^.^{\sqrt{3^2}}$

$-7\sec\left(x-\frac{\pi}{2}\right)$

$\sqrt[3]{16y^5}z^6$

$\frac{dx}{dt}-\left(\frac{1}{t}\right)\cdot x=t\cdot\cos\left(2t\right)$

$\left(-95\right)-\left(-43\right)$