1.25+2.75+1.501.25+2.75+1.501.25+2.75+1.50
limx→1(x4+x−23x3+2x+5)\lim_{x\to1}\left(\frac{x^4+x-2}{3x^3+2x+5}\right)x→1lim(3x3+2x+5x4+x−2)
xy−2x2−y=3\:xy-2x^2-y=3xy−2x2−y=3
∫(x+3)3⋅ ln(x−3) dx\int\left(x+3\right)^3\cdot\:ln\left(x-3\right)\:dx∫(x+3)3⋅ln(x−3)dx
x2−11x=0x^2-11x=0x2−11x=0
y=4x2−16x−2y=\frac{4x^{2}-16}{x-2}y=x−24x2−16
i′=1+2t2ii'=\frac{1+2t}{2i}i′=2i1+2t
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