$\int_{\frac{\pi}{3}}^{3\frac{\pi}{4}}\left(tan4x\right)dx$
$\int\left(5x^2-5x-36\right)dx$
$\left(-5+13\right)\cdot\left(-6\right)$
$20x+10<17x-5$
$\frac{12x+7}{x^2-x-2}$
$v-10=-9$
$\csc\left(x+2\pi\right)\csc\left(x\right)$
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