$\frac{\left(10x^4+10x^3+5x^2-10x-16\right)}{\left(5x+10\right)}$
$\left(15-x\right)\left(5-x\right)$
$\left(6x^3+3\right)\left(6x^3-4\right)$
$sin^4x-cos^4x=2sin^2-1$
$c^2-2cd+d^2$
$5a+2b-c-12-6b$
$8-2\cdot2$
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