$f\left(x\right)=\left(x^2+x\right)\left(x+2\right)$
$\left(8a^2-6ab-27b^2\right)\left(4a-9b\right)$
$5x+41=10x+66$
$y^2-x-4=0$
$\frac{2z^6}{-9x^5z^9}$
$\int_1^4\left(5-2t+3t^2\right)dx$
$-64\tan^2\left(x\right)+16\tan\left(x\right)-71$
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