$-3\:=\:log\left(x\right)$
$\int\frac{\left(2e^x-3\right)e^x}{\left(e^x-1\right)^2}dx$
$-15+4-16+6+2$
$\frac{x^5-3x^2+2x}{x}$
$324,67+45,7+26,8+7$
$12-\left(14-\left(9-15\right)+6\right)$
$a\cdot b=250$
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