$sen^2\left(x\right)=\frac{tan^2\left(x\right)-sen^2\left(x\right)}{sec^2\left(x\right)-1}$
$\int\frac{\left(x+2\right)^2}{x+1}dx$
$\ln x+\ln x=21$
$\left(x^4+6\right)^2$
$5x^2+40x=0$
$2y^3+8y^2+8x$
$\int_0^4\left(\arctan\left(\sqrt{x}\right)\right)dx$
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