$\sqrt[4]{x^{10}}y^8$
$x+\frac{1}{4}>\frac{2}{3}$
$\frac{x^3-2x^2+31x+20}{x+5}$
$\frac{2x^2+x-10}{x-2}$
$\frac{dy}{dx}=\frac{3x^2-e^x}{2y-5}$
$\left(12c-10d\right)^2$
$-6x^2+2x+1$
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