$3a-28-7a=10a$
$4m^2+1=0$
$4x^2+19x-5$
$\int\left(\frac{x^2+4}{x+2}\right)dx$
$\left(-8\right)\cdot999\cdot\left(-125\right)$
$\frac{\sin\left(x\right)}{1-\cos\left(x\right)}\cdot\frac{1+\cos^2\left(x\right)}{1+\cos\left(x\right)}$
$\left(5\:+\:2y\right)^2$
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