$\left(6x+\frac{1}{3}\right)\cdot6x-\frac{1}{3}$
$8^2+4x$
$x+x+3x$
$\lim_{x,y\to0,0}\left(\frac{\left(e^x-1\right)\left(e^{2y}-1\right)}{xy}\right)$
$3x-4y=-26$
$\left(x^2-8\right)\left(x^2+6\right)$
$x^2-22x+48$
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