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Solve the logarithmic equation $\log \left(y+2\right)=1+\log \left(2y-6\right)$

Step-by-step Solution

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Solution

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Final answer to the problem

$y=\frac{62}{19}$
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Step-by-step Solution

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Learn how to solve integrals of rational functions problems step by step online. Solve the logarithmic equation log(y+2)=1+log(2*y+-6). Express the numbers in the equation as logarithms of base 10. Any expression to the power of 1 is equal to that same expression. The sum of two logarithms of the same base is equal to the logarithm of the product of the arguments. For two logarithms of the same base to be equal, their arguments must be equal. In other words, if \log(a)=\log(b) then a must equal b.

Final answer to the problem

$y=\frac{62}{19}$

Exact Numeric Answer

$y=3.2631579$

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Function Plot

Plotting: $\log \left(y+2\right)-1-\log \left(2y-6\right)$

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x
y
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(◻)
+
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×
◻/◻
/
÷
◻2
◻◻
√◻
√

◻√◻
◻√
∞
e
π
ln
log
log◻
lim
d/dx
D□x
∫
∫◻
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

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Main Topic: Integrals of Rational Functions

Integrals of rational functions of the form R(x) = P(x)/Q(x).

Used Formulas

See formulas (2)

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