Exercise
$z=6\left(2t-1\right)^2\left(2-t\right)$
Step-by-step Solution
Learn how to solve two-variable linear equations problems step by step online. Simplify the equation z=6(2t-1)^2(2-t). A binomial squared (difference) is equal to the square of the first term, minus the double product of the first by the second, plus the square of the second term. In other words: (a-b)^2=a^2-2ab+b^2. The power of a product is equal to the product of it's factors raised to the same power. Multiplying polynomials 6 and 4t^2-4t+1. Multiply the single term 6 by each term of the polynomial \left(-4t+1\right).
Simplify the equation z=6(2t-1)^2(2-t)
Final answer to the exercise
$z=72t^2-54t+12-24t^{3}$