$\left|2\left(3\right)-7\right|$
$\frac{x}{4}-12=11$
$\frac{8a^9+27b^6}{2a^3-3b^2}$
$\left(-\frac{4}{5}a^2\right)\left(-\frac{10}{4}b\right)\left(-ab^2\right)$
$\frac{\left(6x^3+27x^2+12x\right)}{\left(x-8\right)}$
$2^4+2^3+2^6$
$\frac{tan-\left(sin\right)cos}{sin^2}$
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