$\int_0^{\frac{\pi}{2}}\left(\frac{1}{cos\left(2x\right)^2}\right)dx$
$\left(x+b\right)\left(x+b\right)^2$
$a-3b-c-c+4b-a$
$\left(3a-2\right)\left(8a-2\right)$
$112+111$
$2x+6<-2$
$4x^2=256$
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