$5x-4y=-38$
$\frac{5x^3-4x+3x^2-7}{x+5}$
$2+5\cdot\left(2\cdot3\right)$
$w-12w+4w^2$
$\frac{6x^4+9x^3-4x^2+10x-3}{3x^2+3x-2}$
$\ln\left(3xy\right)=x+x^5$
$\frac{4}{x-1}+x=7$
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