$2x^{-2}$
$-\frac{2}{5}d-5n$
$\left(x^{n+1}+3\right)\left(x^{n+1}+8\right)$
$\lim_{x\to\infty}\left(7x^3\left(e^{-\frac{1}{x^3}}-1\right)\right)$
$\lim\:_{x\to\:1}\left(\frac{8x^{\frac{7}{4}}-5x^{\frac{4}{5}}-3}{x^2-1}\right)$
$36x^2\:+\:36x\:+\:8$
$-\frac{-10}{1}$
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