limx→∞x2+5x+3−x\lim_{x\to\infty}\sqrt{x^2+5x+3}-xx→∞limx2+5x+3−x
−16x+5≥14-\frac{1}{6}x+5\ge14−61x+5≥14
x2+4x+4+x2−8x+16−x2+3xx^2+4x+4+x^2-8x+16-x^2+3xx2+4x+4+x2−8x+16−x2+3x
r2−8r+16r^2-8r+16r2−8r+16
c2−6c+9c^2-6c+9c2−6c+9
∫((8x+1)2(8))dx\int\left(\left(8x+1\right)^2\left(8\right)\right)dx∫((8x+1)2(8))dx
13⋅12.513\cdot12.513⋅12.5
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