$\frac{d}{dx}\left(arctan\left(8x\right)\right)^2$
$2-8x>-2+x$
$\left(-2a^2+b+3\right)\left(2a^2+2\right)$
$4096\cdot256\cdot16$
$13\:+\:t\:=\:51$
$8x^3+3\left(4x\right)^21+3\left(2x\right)\left(1\right)^2+1^3$
$\left(\sqrt{a^2}\right)^2$
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