$e=cos\:\left(x+y\right)$
$3x^2-5x+4x=-3$
$16\csc\left(\theta\right)-16=0$
$\frac{\left(1.980\right)\left(6.79\right)}{\left(4.1\right)\left(3.28\right)}$
$24x^4y^22+18x^3y^42^3-6x^5y^3$
$\frac{1\:-b^{12}}{1-b^3}$
$\left(x+\frac{1}{2}\right)dy+ydx=0$
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