$\frac{dy}{dx}=4x+xy\:,\:y\left(0\right)=1$
$9+12f+4f^2$
$\left(5\right)\left(5+4\right)$
$25x^8-49f^{12}$
$5\cdot\left(x+2\right)<3\cdot\left(x+3\right)+1$
$\left(t-1\right)\left(t+5\right)$
$25b^2-9=40$
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