$\frac{x^4-4}{x+2}$
$x2\:-\:16x\:=\:0$
$2xy\left(3x^2-4y^3\right)$
$t\frac{dx}{dt}=x-1$
$\int\sqrt[3]{1-3x\:}dx$
$36m^2n^2-48mnxy+16x^2y^2$
$2\cdot5a$
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