$f\left(x\right)=\left(3x^3-12\right)\tan\left(x\right)$
$\left(x-4\right)^2=16$
$2x-12<8$
$k^2+11k^230$
$\:\frac{tan\theta+cot\theta\:\:}{sec\theta csc\theta\:\:}$
$\frac{a^2}{4}-\frac{b}{16}$
$x^3-2x+4x^3+1-6x^3+3-1$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!