limx→0(1+x+1x)\lim_{x\to0}\left(\frac{1+\sqrt{x+1}}{x}\right)x→0lim(x1+x+1)
2x−3y+9y−2x+10y2x-3y+9y-2x+10y2x−3y+9y−2x+10y
−3−2−6−162−(−3−1)\frac{-3^{-2}-6^{-1}}{6^2-\left(-3^{-1}\right)}62−(−3−1)−3−2−6−1
(u2w2)(u−1v22w−3)2\left(\frac{u^2}{w^2}\right)\left(\frac{u^{-1}v^2}{2w^{-3}}\right)^2(w2u2)(2w−3u−1v2)2
y2+15y+15y^2+15y+15y2+15y+15
(4x2−5y)2\left(4x^2-5y\right)^2(4x2−5y)2
(m−4)−8\left(m^{-4}\right)^{-8}(m−4)−8
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