$\int\:\frac{x^2-4x-4}{\left(x-3\right)\left(x^2+2\right)}dx$
$8x-4+3x+4x+14$
$\frac{1}{x^2}=\frac{1}{x}-\frac{1}{2}$
$-7x<42$
$m^2-11m+30\left(m-6\right)$
$\lim_{y\to\pi}\frac{\sin^2y}{1+\cos\left(y\right)}$
$-8-\left(-10\right)^3$
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