$12,62-20,345+7,1234$
$\frac{1}{16+4x^2}$
$-\left[\:\left(-5\:+4\right)\:-\:\left(-8\:-7\right)\:+\:\left(-8+4\right)\right]$
$x^{\frac{4}{3}}-\frac{1}{6}x^{-\frac{4}{3}}+\frac{1}{2}$
$25a^4+30a^2b+9b^2$
$x^2-3x>10$
$\lim_{x\to0}\left(\frac{\sin\left(x\right)\left(1-\cos\left(x\right)\right)}{2x^2}\right)$
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