$$f\left(x\right)=2x\frac{3}{4}+4x-\frac{1}{4}$$

$$x^2+5x-5=0$$

$$\cot ydx=\tan xdy$$

$$\int\frac{x+5}{\left(x+3\right)\left(x+1\right)}dx$$

$$\int\:3cosh^2\left(x-3\right)sinh\left(x-3\right)dx$$

$$\left(2w^4\right)^3$$

$$y'=\frac{y+\sqrt{y^2-4x^2}}{x}$$