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Exercise

y′=(x5+2)2(x3+4)4y'=\left(x^5+2\right)^2\left(x^3+4\right)^4

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Final answer to the exercise

y=x2323+45x20+96x1717+1287x14+256x1111+29x18+64x1515+32x12+1024x99+5123x6+4x1313+325x10+384x77+256x4+1024x+C0y=\frac{x^{23}}{23}+\frac{4}{5}x^{20}+\frac{96x^{17}}{17}+\frac{128}{7}x^{14}+\frac{256x^{11}}{11}+\frac{2}{9}x^{18}+\frac{64x^{15}}{15}+32x^{12}+\frac{1024x^{9}}{9}+\frac{512}{3}x^{6}+\frac{4x^{13}}{13}+\frac{32}{5}x^{10}+\frac{384x^{7}}{7}+256x^{4}+1024x+C_0

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y'=(x5+2)2(x3+4)4
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