$\lim_{x\to0}\left(\frac{\arctan\left(x^2\right)}{2x^2-1}\right)$

$\left(-8x-8^2\right)$

$\int\left(\frac{32x^2}{\left(x-18\right)\left(x+6\right)^2}\right)dx$

$\left(x^3+x-1\right)\left(x+3\right)^2-5$

$\left|\left(-14\right)+15\right|\cdot\left(-16\right)+\left(-27\right)$

$-3\left(-2q+2\right)$

$-2z^2-z^2$