$\frac{dy}{dx}=\left(\tan\right)^2\left(x+y\right)$

$\int\frac{1}{\left(3x+6\right)^4}dx$

$4y^2+20y-25$

$\left(\frac{-3x^2}{4}\right)\left(\frac{4}{9}x^2-\frac{5}{3}x+\frac{4}{9}\right)$

$3000\left(1+0.1\right)^3$

$36+24x-16x-x+x$

$\int_0^0\left(\sin\left(x\right)\left(\sin\left(2x\right)\sin\left(3x\right)\right)\right)dx$