$\int\frac{1}{\sec^4\left(x\right)}dx$
$8x-0.02x^2$
$\tan^5\left(x\right)-9\tan\left(^2\right)=0$
$-\left(x-3\right)\left(x-1\right)$
$\int\left(\sqrt{1-4\cdot x}\right)$
$\left(x^2+y^2\right)^3b\cdot\left(a+8\right)\left(a+7\right)$
$y^2+\frac{2y}{3}$
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