$sen^2a\cdot sec^2a\cdot ctg^2a=1$
$\frac{1}{5}\sqrt{50}-2\sqrt{18}+8\sqrt{2}$
$+2+\left(-8\right)$
$\frac{dy}{dx}+3x=0$
$\left(-9x^3\:+4y\right)^2$
$a^2\cdot\:\left(a+4\right)^2$
$5.50-10$
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