$12z-4$
$32x^2-16x+2$
$\left(x^2-x-1\right)\left(x+4\right)$
$4x^2+10xy+6y^2$
$\int\frac{\left(z^4+10z^3\right)}{2x^2}dz$
$\lim_{x\to2}\left(\frac{x^3-8}{x^3+2x^2-5x+6}\right)$
$\left(\frac{\frac{-6x^3}{5}}{\frac{-2x}{5}}\right)$
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