$\frac{3x^2\cdot\left(-4x^3\right)}{16x^2}$

$v_o=2,a=3,t=2,x_o=5\:$

$\int_{1.167}^{0.5}\left(\frac{1}{\ln\left(6x\right)}\right)dx$

$\frac{6x}{3}$

$\left(-2x^3+5x^2+2\right)-\left(8x^3+4x^2-5\right)$

$\left(3\:senx\:+\:2\:cos\:x\right)^2\:+\:\left(2\:sen\:x\:-\:3\:cos\:x\right)^2$

$5x+2\ge3x+8$