$cos^2\theta\:+cos\theta\:=sin^2\theta\:$
$x3-x^2-4x+4$
$-8\left|3\right|$
$\int x\sqrt{x+12}\:dx$
$\sqrt[3]{2.52}$
$-48x+3x^2+3x^3-9x-9x^2-3x^3$
$\frac{x^2-9x+14}{x-2}$
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