$-6561-15309$
$585+495$
$\lim_{x\to0}\left(\frac{\sin\left(4x\right)\left(\tan\left(3x\right)\right)^2}{6x^3}\right)$
$\frac{1}{\sec\left(a\right)-\tan\left(a\right)}$
$3x^2-12xy-2x+8y$
$-5ydy=3dt$
$\lim_{x\to6}\left(\frac{-4+3e^{12-2x}}{x^2-36}\right)$
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