$3 x ^ { 3 } - 6 x$
$1+\tan^2\left(a\right)=\sec^2\left(a\right)$
$-x^2-10x$
$41^{\infty}$
$\left(a^3b^4+\left(-5\right)\right)^2$
$\left(ax^{-\frac{1}{2}}+xa^{-17}\right)^n$
$14m^2\:n^2-7mn+35m^7\:n^3$
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