$5x-7<=16x+1$
$3\left(x+9\right)=2.4$
$\lim_{x\to-1}\left(\frac{2x^3+4x^2+2x}{\left(x+1\right)^2}\right)$
$\frac{dy}{dt}=t^{-2}\left(sen2t-2ty\right)$
$x^2=50$
$3j^{-3}\:x\:-6j^{4\:}x\:2j^5$
$\frac{cos2x}{cosx+sinx}=cosx-sinx\:$
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