$20\left(4x+\frac{1}{3}\right)\left(4x+\frac{3}{4}\right)$
$\left(\frac{1}{4^{2x+1}}\right)$
$3x-5<8$
$\frac{a^3}{4}+a^6+a^7$
$\left(3m-5p\right)^2$
$100-x=5\left(z\right)$
$\left(3x-2x^2\right)\left(5+4x\right)$
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