$\tan\left(teta\right)=-\frac{\sqrt{6}}{3}$
$y\cdot y^2$
$\frac{3}{4}x\frac{-2}{9}-1\frac{1}{2}+\frac{7}{8}:\frac{7}{3}$
$\lim_{y\to0}\left(\frac{y^2-3y}{y^2+4y+3}\right)$
$2j+1\le-1$
$\left(6m^3-8m^2n+20mn^2\right)$
$\left(5500\right)^0$
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