$\left(a^2-b^2\:\right)\left(x^2+1\right)+2\left(a^2+b^2\:\right)x$
$x^8-\left(3yz\right)^4$
$5\cdot\sqrt[2]{1}$
$\lim_{x\to+00}\:\frac{\ln\left(e^x-x\right)}{x}$
$\frac{5}{8}\frac{8}{5}$
$-21m^2n+83mn^3$
$2x\left(x-8\right)$
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