$x^6-4x^3+4$
$\lim_{x\to3}x^2+6x-40$
$\frac{5-z}{2}=2z$
$\:r=ln\left(2x\right)$
$0.4x+3.9=5.78$
$\frac{1}{6x^{2}+\frac{1}{3}x}+\frac{4}{9}$
$1+6x+6x+8$
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