$x+4-00$
$x=y^2\frac{dy}{dx}$
$9z^4-3+4z^2-z-8z^2+2$
$4x+5-x+1$
$\frac{dy}{dx}=5e^{4x}y$
$\frac{d}{ds}s=\sqrt{t}-\sqrt[3]{t}$
$\lim_{x\to\infty}\left(\frac{x^2+x-2}{x-1}\right)$
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