$\int\left(\frac{t^2}{\sqrt{t^3+4}}\right)dt$
$\frac{d^2}{dx^2}\left(2x-3y+d\right)$
$\frac{dy}{dx}=\frac{yx}{-\left(x+1\right)}$
$-4y+15\:=\:19$
$3x^2-36x+60$
$\frac{1}{2}\cdot400\cdot04^2$
$14\cdot300$
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