$-1+2-3+4-5+6$
$\lim_{x\to\infty}\left(\frac{6x^4}{e^x}\right)$
$\left(3x+2y\right)^2-\left(y-4\right)^2$
$\lim_{x\to0}\frac{e^{ax}-1}{e^{bx}-1}$
$\left(\left(\frac{9}{-1-x}\right)\right)$
$18\cdot6\left(-9\right)$
$\frac{2x^3-x-12}{x+3}$
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