$\frac{-2h^2+h}{\left(h^2+1\right)\left(h\right)}$

$\lim_{x\to\infty}\left(\frac{\sqrt{x^2-2x+4}-\sqrt{x^2-6x+3}}{1}\right)$

$x+10+x+5$

$\int_{-\infty}^5\left(3e^{3x}\right)dx$

$\int\tan\left(-x\right).\sec\left(-x\right)^2dx$

$\frac{dy}{dx}=y\left(x\right)\left(4-y\left(x\right)\right)-3$

$\left(4x\:+8y+3\right)^2$